A woman is tested and has one allele for Huntington's disease. Her partner does not have the allele. What is the chance that their first child inherits it, and why is this different from cystic fibrosis?
- Huntington's is caused by a dominant allele, so she is heterozygous: one Huntington's allele and one normal allele.
- Half of her eggs carry the Huntington's allele; all of her partner's sperm carry the normal allele.
- So the chance for each child is 1 in 2, and a child with the allele will develop the disease.
- Cystic fibrosis is recessive, so a child must inherit the allele from both parents.
Answer: 1 in 2 (50%) for each child.