Catalase is added to hydrogen peroxide. 24 cm3 of oxygen is collected in the first 30 s and a total of 30 cm3 after 60 s. What is the initial rate, and why is the reaction slower in the second 30 s?
- initial rate = volume of oxygen ÷ time = 24 ÷ 30 = 0.8 cm3 s−1.
- In the second 30 s only 30 − 24 = 6 cm3 is made: 6 ÷ 30 = 0.2 cm3 s−1.
- Substrate has been used up, so its concentration is lower and fewer enzyme-substrate complexes form each second.
Answer: The initial rate is 0.8 cm3 s−1; the rate falls because the substrate concentration falls.