1.85 g of propanoyl chloride, CH3CH2COCl (Mr 92.5), reacts completely with excess ethanol. What mass of ester (Mr 102) is formed?
- CH3CH2COCl + CH3CH2OH → CH3CH2COOCH2CH3 + HCl, so the ratio is 1 : 1.
- Moles of propanoyl chloride = 1.85 ÷ 92.5 = 0.0200 mol.
- Mass of ethyl propanoate = 0.0200 × 102 = 2.04 g.
Answer: 2.04 g of ethyl propanoate