Propanoyl chloride reacts with ammonia to give propanamide. Name the type of mechanism and the small molecule eliminated.
- Ammonia has a lone pair on N, so it acts as a nucleophile and attacks the δ+ carbon of the C=O group (addition).
- The C=O bond then forms again and Cl− leaves; an H+ is lost from the nitrogen (elimination).
- Overall: CH3CH2COCl + NH3 → CH3CH2CONH2 + HCl.
Answer: Addition–elimination; HCl is eliminated (with excess ammonia it is seen as NH4Cl).