Complexes of copper(I), such as [Cu(NH3)2]+, are colourless, but complexes of copper(II) are coloured. Why?
- Cu+ is [Ar] 3d10; Cu2+ is [Ar] 3d9.
- In Cu+ all five d orbitals are full, so there is no space in the higher set for an electron to move into.
- In Cu2+ one higher d orbital is half-filled, so an electron can be promoted by absorbing visible light of energy ΔE.
Answer: Cu+ (3d10) cannot absorb visible light by promoting a d electron, so it is colourless; Cu2+ (3d9) can, so it is coloured.