Poly(lactic acid) has the repeat unit –O–CH(CH3)–CO– (Mr 72). What mass of NaOH (Mr 40) is needed to hydrolyse 7.2 g of the polymer completely, and what is the organic product?
- Each repeat unit has one ester link, so it needs one NaOH: the product is CH3CH(OH)COO−Na+.
- Moles of repeat units = 7.2 ÷ 72 = 0.10 mol.
- Moles of NaOH = 0.10 mol, so mass = 0.10 × 40 = 4.0 g.
Answer: 4.0 g of NaOH; the product is sodium 2-hydroxypropanoate