A current of 0.800 A is passed through concentrated aqueous sodium chloride for 40.0 minutes. What volume of chlorine forms at the anode at room conditions? (F = 96 500 C mol−1; molar gas volume = 24.0 dm3 mol−1)
- Q = It = 0.800 × (40.0 × 60) = 0.800 × 2400 = 1920 C.
- Moles of electrons = 1920 ÷ 96 500 = 0.01990 mol.
- 2Cl− → Cl2 + 2e−, so moles of Cl2 = 0.01990 ÷ 2 = 0.00995 mol.
- Volume = 0.00995 × 24.0 = 0.239 dm3.
Answer: 0.239 dm3 of chlorine