2.82 g of phenol (Mr 94.0) reacts completely with excess sodium. What volume of hydrogen, measured at room conditions, is produced? (molar gas volume 24.0 dm3 mol−1)
- Moles of phenol = 2.82 ÷ 94.0 = 0.0300 mol.
- 2C6H5OH + 2Na → 2C6H5O−Na+ + H2, so moles of H2 = 0.0300 ÷ 2 = 0.0150 mol.
- Volume = 0.0150 × 24.0 = 0.360 dm3.
Answer: 360 cm3 of hydrogen