Equilibrium of a rigid body

Further Maths · Further Mechanics. The idea in plain words, the rules to remember, the mistake to avoid and a worked example, written and checked by Mega Lecture.

Test this topic freeAll Further Maths topics

The idea

A rigid body has size, so a force can turn it as well as push it. The turning effect of a force about a point is its moment: the force multiplied by the perpendicular distance from the point to the line of action of the force.

The whole weight of a body can be treated as one force acting at its centre of mass. For a uniform body this point lies on every line of symmetry. For a composite body, replace each part by a particle at its own centre of mass and take moments.

A body is in equilibrium when the forces balance in every direction and the moments about any point balance. On a slope a body may slide or topple, so test which happens first.

Rules to remember

Common mistake

Students multiply the force by the distance to the point where it acts, not by the perpendicular distance to its line of action. If the force is at an angle, first resolve it or use Fd sin θ.

Worked example

A uniform L-shaped lamina has vertices at (0, 0), (6, 0), (6, 2), (2, 2), (2, 8) and (0, 8), with units in cm. Find the coordinates of its centre of mass.

  1. Split into rectangle A (0 ≤ x ≤ 6, 0 ≤ y ≤ 2): area 12, centre (3, 1); and rectangle B (0 ≤ x ≤ 2, 2 ≤ y ≤ 8): area 12, centre (1, 5).
  2. x̄ = (12 × 3 + 12 × 1) ÷ 24 = 48 ÷ 24 = 2.
  3. ȳ = (12 × 1 + 12 × 5) ÷ 24 = 72 ÷ 24 = 3.

Answer: (2, 3)

Ask about this

Type what you are stuck on. The helper finds the explanation, worked examples and the notes to read, free and instant.

Keep going

← Motion of a projectileCircular motion →Take a Further Maths test