A random sample of 16 observations from a normal population has mean 52.1 and unbiased variance estimate 16. Test at the 5% significance level H0: μ = 50 against H1: μ > 50. The critical value of t for ν = 15 is 1.753.
- s = √16 = 4, so the standard error is s/√n = 4/√16 = 1.
- t = (52.1 − 50) ÷ 1 = 2.1, with ν = 16 − 1 = 15.
- 2.1 > 1.753, so the result is in the critical region.
Answer: Reject H0: there is evidence at the 5% level that the population mean is greater than 50.