An alternating p.d. V = 80 sin (120πt), with V in volts and t in seconds, is applied across a 40 Ω resistor. What are the frequency and the mean power?
- Compare with V = V0 sin ωt: V0 = 80 V and ω = 120π rad s−1.
- f = ω ÷ 2π = 120π ÷ 2π = 60 Hz.
- Vr.m.s. = 80 ÷ √2 = 56.6 V.
- Mean power = Vr.m.s.2 ÷ R = 3200 ÷ 40 = 80 W.
Answer: 60 Hz and 80 W