Discharging a capacitor

Physics A2 · Capacitance. The idea in plain words, the rules to remember, the mistake to avoid and a worked example, written and checked by Mega Lecture.

Test this topic freeAll Physics A2 topics

The idea

When a charged capacitor is connected across a resistor, charge flows off the plates through the resistor. The charge Q, the p.d. V and the current I all fall with time.

The fall is an exponential decay. The current depends on the p.d., and the p.d. depends on the charge left, so the less charge there is, the more slowly it leaves. Each quantity falls by the same fraction in equal time intervals and never quite reaches zero.

The time constant τ = RC sets how fast this happens. After one time constant each quantity has fallen to 1/e, about 37%, of its starting value.

Rules to remember

Common mistake

After one time constant the quantity has fallen TO 37% of its starting value, not BY 37%. In the exponent, keep the minus sign and use R in Ω and C in F.

Worked example

A 200 μF capacitor is charged to 6.0 V and then discharged through a 50 kΩ resistor. What is the p.d. across it after 15 s?

  1. τ = RC = 50 × 103 × 200 × 10−6 = 10 s.
  2. V = V0e−t/RC = 6.0 × e−15/10 = 6.0 × e−1.5.
  3. e−1.5 = 0.223, so V = 6.0 × 0.223 = 1.3 V.

Answer: 1.3 V

Ask about this

Type what you are stuck on. The helper finds the explanation, worked examples and the notes to read, free and instant.

Read the full notes

Keep going

← Energy stored in a capacitorConcept of a magnetic field →Take a Physics A2 test