Point charges of +2.0 nC and +8.0 nC are 0.30 m apart in a vacuum. What is the electric field strength at the midpoint between them?
- The midpoint is 0.15 m from each charge, so r2 = 0.0225 m2.
- Field of the +2.0 nC charge: 8.99 × 109 × 2.0 × 10−9 ÷ 0.0225 = 799 N C−1, pointing away from it.
- Field of the +8.0 nC charge: 8.99 × 109 × 8.0 × 10−9 ÷ 0.0225 = 3196 N C−1, pointing away from it.
- The two fields are opposite, so the resultant = 3196 − 799 = 2397 N C−1, in the direction of the larger field.
Answer: 2.4 × 103 N C−1, directed towards the +2.0 nC charge.