A small droplet with a charge of +4.8 × 10−19 C experiences an upward electric force of 9.6 × 10−15 N. What is the electric field strength there, and what is the force on an electron at the same point?
- E = F ÷ q = 9.6 × 10−15 ÷ 4.8 × 10−19 = 2.0 × 104 N C−1.
- The droplet is positive, so the field is in the direction of the force: upwards.
- Force on an electron: F = qE = 1.60 × 10−19 × 2.0 × 104 = 3.2 × 10−15 N.
- The electron is negative, so this force is opposite to the field: downwards.
Answer: E = 2.0 × 104 N C−1 upwards; the force on the electron is 3.2 × 10−15 N downwards.