A wire of length 0.12 m carries a current of 5.0 A at right angles to a uniform magnetic field. The force on the wire is 0.030 N. What is the flux density?
- The wire is perpendicular to the field, so F = BIL.
- Rearrange: B = F ÷ (IL) = 0.030 ÷ (5.0 × 0.12).
- B = 0.030 ÷ 0.60 = 0.050 T.
Answer: 0.050 T