Gravitational field of a point mass

Physics A2 · Gravitational fields. The idea in plain words, the rules to remember, the mistake to avoid and a worked example, written and checked by Mega Lecture.

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The idea

The field strength around a point mass M comes from two equations. Newton's law gives the force on a small mass m as F = GMm/r2. The definition of field strength is g = F/m. Dividing, m cancels, which leaves g = GM/r2. So g depends only on the mass causing the field and the distance from its centre.

This is an inverse square law: at twice the distance from the centre, g is one quarter as large. The equation also works at and above the surface of a uniform spherical planet.

Near the Earth's surface, a change in height of a few kilometres is tiny compared with the Earth's radius. So r hardly changes and g is approximately constant.

Rules to remember

Common mistake

When g falls to one quarter, r has doubled to 2R, but the height above the surface is only R. Students often give 2R as the height. Height = r − R.

Worked example

The Earth has mass 5.97 × 1024 kg and radius 6.37 × 106 m. What is the gravitational field strength 3.0 × 105 m above its surface?

  1. Distance from the centre: r = 6.37 × 106 + 0.30 × 106 = 6.67 × 106 m.
  2. r2 = (6.67 × 106)2 = 4.45 × 1013 m2.
  3. g = GM/r2 = (6.67 × 10−11 × 5.97 × 1024) ÷ 4.45 × 1013 = 3.98 × 1014 ÷ 4.45 × 1013.

Answer: About 8.9 N kg−1 (8.95).

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