The Earth has mass 5.97 × 1024 kg and radius 6.37 × 106 m. What is the gravitational field strength 3.0 × 105 m above its surface?
- Distance from the centre: r = 6.37 × 106 + 0.30 × 106 = 6.67 × 106 m.
- r2 = (6.67 × 106)2 = 4.45 × 1013 m2.
- g = GM/r2 = (6.67 × 10−11 × 5.97 × 1024) ÷ 4.45 × 1013 = 3.98 × 1014 ÷ 4.45 × 1013.
Answer: About 8.9 N kg−1 (8.95).