A line of laboratory wavelength 486.1 nm is observed at 500.7 nm in the light from a galaxy. Taking H0 = 2.2 × 10−18 s−1, how far away is the galaxy?
- Δλ = 500.7 − 486.1 = 14.6 nm, so Δλ/λ = 14.6 ÷ 486.1 = 0.0300.
- v = 0.0300 × c = 0.0300 × 3.00 × 108 = 9.0 × 106 m s−1.
- d = v ÷ H0 = (9.0 × 106) ÷ (2.2 × 10−18) = 4.1 × 1024 m.
Answer: About 4.1 × 1024 m.