A carbon-12 nucleus has mass 11.996706 u. Proton mass = 1.007276 u, neutron mass = 1.008665 u. What is its binding energy per nucleon?
- Mass of 6 protons and 6 neutrons = 6 × 1.007276 + 6 × 1.008665 = 12.095646 u.
- Mass defect = 12.095646 − 11.996706 = 0.098940 u = 0.098940 × 1.66 × 10−27 = 1.64 × 10−28 kg.
- Binding energy = c2Δm = (3.00 × 108)2 × 1.64 × 10−28 = 1.48 × 10−11 J = 92.4 MeV.
- Per nucleon: 92.4 ÷ 12 = 7.7 MeV.
Answer: About 7.7 MeV per nucleon (1.2 × 10−12 J).