Radiation of wavelength 300 nm falls on a metal of work function 2.5 eV. What is the maximum kinetic energy of the photoelectrons?
- Photon energy = hc/λ = (6.63 × 10−34 × 3.00 × 108) ÷ (3.00 × 10−7) = 6.63 × 10−19 J.
- Work function = 2.5 × 1.60 × 10−19 = 4.0 × 10−19 J.
- Maximum kinetic energy = 6.63 × 10−19 − 4.0 × 10−19 = 2.63 × 10−19 J.
Answer: About 2.6 × 10−19 J (1.6 eV).