A spaceship of proper length 120 m passes the Earth at 0.8c (c = 3 × 108 m s−1). Find its length in the Earth frame and the time it takes to pass a fixed point on Earth.
- γ = 1/√(1 − 0.82) = 1/√0.36 = 1/0.6 = 1.67.
- Length in the Earth frame: L = L0/γ = 120 × 0.6 = 72 m.
- Speed = 0.8 × 3 × 108 = 2.4 × 108 m s−1.
- Time to pass = 72 ÷ (2.4 × 108) = 3.0 × 10−7 s.
Answer: 72 m; 3.0 × 10−7 s (0.30 μs).