A Carnot engine works between 227 °C and 27 °C and takes in 1000 J of heat per cycle. Find its efficiency, the work done and the heat rejected.
- Convert: Thot = 227 + 273 = 500 K; Tcold = 27 + 273 = 300 K.
- Efficiency = 1 − 300 ÷ 500 = 0.40 (40%).
- Work done = 0.40 × 1000 = 400 J; heat rejected = 1000 − 400 = 600 J.
- Check with entropy: 1000 ÷ 500 = 2 J K−1 in and 600 ÷ 300 = 2 J K−1 out, as a reversible cycle needs.
Answer: 40%; 400 J of work; 600 J rejected.