The 4th term of an arithmetic sequence is 11 and its 10th term is 29. The sum of its first 10 terms is
- T10 − T4 = 6d, so 6d = 29 − 11 = 18 and d = 3.
- T4 = a + 3d = 11, so a = 11 − 9 = 2.
- S10 = (10/2)(a + l) = 5 × (2 + 29) = 5 × 31 = 155.
Answer: 155
NUST NET Maths · Maths · Sequences, series and the binomial theorem. The idea in plain words, the rules to remember, the mistake to avoid and a worked example, written and checked by Mega Lecture.
In an arithmetic sequence you add the same number d each time. In a geometric sequence you multiply by the same number r each time. Almost every question gives you two facts and expects you to find the first term a and then d or r.
A geometric series can be summed for ever only when its terms shrink, that is when |r| < 1. If |r| ≥ 1 there is no sum to infinity.
Means are terms placed between two numbers so that the whole list forms a sequence. A harmonic sequence is one whose reciprocals are in arithmetic sequence, so harmonic questions are solved by turning every term upside down first.
Using n in place of n − 1 in the term formulas. The 10th term of an arithmetic sequence is a + 9d, and the 6th term of a geometric sequence is ar5.
Answer: 155
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