For y = 5 cos 2x, find the period, the maximum value and the smallest positive x at which the minimum occurs.
- Period = 2π ÷ 2 = π.
- cos 2x lies between −1 and 1, so the maximum of y is 5 × 1 = 5 and the minimum is 5 × (−1) = −5.
- The minimum occurs when cos 2x = −1, so 2x = π and x = π/2.
Answer: Period π; maximum value 5; the minimum −5 first occurs at x = π/2.