Write the recurring decimal 0.363636... as a common fraction.
- 0.363636... = 0.36 + 0.0036 + 0.000036 + ..., a G.P. with a = 0.36 and r = 0.01.
- |r| < 1, so S∞ = a/(1 − r) = 0.36/(1 − 0.01) = 0.36/0.99.
- = 36/99 = 4/11.
Answer: 0.363636... = 4/11
Maths · Sequences and series. The idea in plain words, the rules to remember, the mistake to avoid and a worked example, written and checked by Mega Lecture.
A geometric progression (G.P.) is a sequence in which each term is found by multiplying the term before it by the same non-zero number. That number is the common ratio r, and the first term is a. No term of a G.P. is zero.
A geometric mean (G.M.) is a number placed between two numbers so that all of them are in G.P. If a, b, c are in G.P., then b2 = ac.
When |r| < 1 the terms get smaller and smaller, so the sum of infinitely many terms settles at a fixed value, the sum to infinity. A recurring decimal is a series of this kind, which is how it is changed into a common fraction.
Students use a/(1 − r) when |r| ≥ 1. An infinite geometric series has a sum only when |r| < 1, so check r first. Also keep the sign of a negative r inside brackets when you raise it to a power.
Answer: 0.363636... = 4/11
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