Show by mathematical induction that 9n − 1 is divisible by 8 for every positive integer n.
- n = 1: 91 − 1 = 8, which is divisible by 8, so condition 1 holds.
- Assume it is true for n = k: 9k − 1 = 8m for some integer m.
- For n = k + 1: 9k+1 − 1 = 9 × 9k − 1 = 9(9k − 1) + 8 = 9(8m) + 8.
- = 8(9m + 1), which is divisible by 8, so condition 2 holds.
Answer: Both conditions hold, so 9n − 1 is divisible by 8 for all positive integers n.