Find the solution set of √(2x + 3) = x.
- Square both sides: 2x + 3 = x2, so x2 − 2x − 3 = 0.
- Factorise: (x − 3)(x + 1) = 0, so x = 3 or x = −1.
- Check x = 3: √(6 + 3) = √9 = 3, which equals x. Accept.
- Check x = −1: √(−2 + 3) = √1 = 1, which is not −1. Reject (extraneous root).
Answer: Solution set = {3}