Water (ρ = 1000 kg m−3) flows at 1.5 m s−1 through a horizontal pipe of area 6.0 cm2, which narrows to 2.0 cm2. Find the pressure difference between the two sections.
- Continuity: v2 = A1v1/A2 = (6.0 × 1.5)/2.0 = 4.5 m s−1.
- v22 − v12 = 20.25 − 2.25 = 18 m2 s−2.
- P1 − P2 = ½ × 1000 × 18 = 9000 Pa.
Answer: 9.0 kPa, with the lower pressure in the narrow section