A 2.0 kg ball moving at 6.0 m s−1 makes a head-on elastic collision with a 1.0 kg ball at rest. Find both velocities after the collision.
- v1′ = (m1 − m2)v1/(m1 + m2) = (2.0 − 1.0) × 6.0 ÷ 3.0 = 2.0 m s−1.
- v2′ = 2m1v1/(m1 + m2) = 2 × 2.0 × 6.0 ÷ 3.0 = 8.0 m s−1.
- Check momentum: before = 2.0 × 6.0 = 12; after = 2.0 × 2.0 + 1.0 × 8.0 = 12 kg m s−1.
Answer: The 2.0 kg ball moves on at 2.0 m s−1 and the 1.0 kg ball moves at 8.0 m s−1, both in the original direction