A uniform metre rule of weight 1.0 N is pivoted at the 30 cm mark. What weight W hung at the 5 cm mark keeps it horizontal?
- The rule's weight acts at the 50 cm mark, 0.20 m from the pivot. W acts 0.25 m from the pivot on the other side.
- Second condition: W × 0.25 = 1.0 × 0.20.
- W = 0.20 ÷ 0.25 = 0.80 N.
Answer: W = 0.80 N (the pivot then pushes up with 1.0 + 0.80 = 1.8 N)