A 0.20 kg ball is thrown straight up at 14 m s−1 and rises to a height of 9.0 m. How much work is done against air resistance on the way up?
- K.E. at the start = ½mv2 = ½ × 0.20 × 142 = 19.6 J.
- P.E. at the top = mgh = 0.20 × 9.8 × 9.0 = 17.64 J (the K.E. there is zero).
- Work done against air resistance = 19.6 − 17.64 = 1.96 J.
Answer: About 2.0 J