A, B, C and D lie on a circle with centre O. Angle BOD = 152°. A is on the major arc BD and C is on the minor arc BD. Find angle BCD.
- Angle BAD is at the circumference on the same arc as angle BOD, so angle BAD = 152° ÷ 2 = 76°.
- ABCD is a cyclic quadrilateral, so angle BAD + angle BCD = 180°.
- Angle BCD = 180° − 76° = 104°.
Answer: Angle BCD = 104°