Find the nth term of the quadratic sequence 2, 9, 22, 41, 66, …
- First differences: 7, 13, 19, 25. Second differences: 6, 6, 6, so a = 6 ÷ 2 = 3.
- Subtract 3n2 (3, 12, 27, 48, 75) from the terms: −1, −3, −5, −7, −9.
- This is a linear sequence going down in 2s with first term −1, so its nth term is −2n + 1.
- Check with n = 4: 3(16) − 8 + 1 = 41.
Answer: 3n2 − 2n + 1