An ultrasound pulse is sent into a steel block, where sound travels at 5000 m/s. The echo from a crack returns 4.0 × 10−5 s later. How far below the surface is the crack?
- Distance travelled = speed × time = 5000 × 4.0 × 10−5 = 0.20 m.
- This is the distance to the crack and back.
- Depth = 0.20 ÷ 2 = 0.10 m.
Answer: 0.10 m (10 cm)