For y = 5 − 2cos 4x, find the period, the minimum value and the smallest positive x at which the minimum occurs.
- Period = 2π ÷ b = 2π ÷ 4 = π/2.
- The minimum of 5 − 2cos 4x happens when cos 4x = 1: y = 5 − 2 = 3.
- cos 4x = 1 when 4x = 0, 2π, ...; the smallest positive value is 4x = 2π, so x = π/2.
Answer: Period π/2; minimum value 3, first reached for positive x at x = π/2.