f(x) = (x − 1)2 + 2 for x ≥ 1. Find f−1(x) and its domain.
- Write y = (x − 1)2 + 2 and swap: x = (y − 1)2 + 2.
- (y − 1)2 = x − 2, so y − 1 = √(x − 2). The positive root is taken because y ≥ 1.
- The range of f is y ≥ 2, so the domain of f−1 is x ≥ 2.
- Check: f(3) = 4 + 2 = 6 and f−1(6) = 1 + √4 = 3.
Answer: f−1(x) = 1 + √(x − 2), with domain x ≥ 2