An open box with a square base of side x cm must hold 32 cm3. Its surface area is S = x2 + 128/x. Find the minimum surface area.
- Write S = x2 + 128x−1, so dS/dx = 2x − 128x−2
- Set dS/dx = 0: 2x = 128/x2, so x3 = 64 and x = 4
- Check: at x = 2, dS/dx = 4 − 32 = −28 (negative); at x = 8, dS/dx = 16 − 2 = 14 (positive), so it is a minimum
- S = 42 + 128 ÷ 4 = 16 + 32 = 48
Answer: Minimum surface area = 48 cm2, when x = 4 cm.