A flask of volume 2.0 × 10−3 m3 holds an ideal gas at a pressure of 1.5 × 105 Pa and a temperature of 300 K. How many molecules are in the flask? (kB = 1.38 × 10−23 J K−1)
- Use pV = NkBT, so N = pV ÷ (kBT).
- pV = 1.5 × 105 × 2.0 × 10−3 = 300 J.
- kBT = 1.38 × 10−23 × 300 = 4.14 × 10−21 J.
- N = 300 ÷ (4.14 × 10−21) = 7.2 × 1022.
Answer: About 7.2 × 1022 molecules.