A ball is thrown horizontally at 6.0 m s−1 from a window and hits the ground 1.5 s later. Air resistance is negligible and g = 9.8 m s−2. What is its speed as it hits the ground?
- The horizontal velocity does not change: 6.0 m s−1.
- Vertical velocity: v = u + at = 0 + 9.8 × 1.5 = 14.7 m s−1.
- Combine the components: speed = √(6.02 + 14.72) = √(36 + 216) = √252.
Answer: About 16 m s−1.