An electron in a hydrogen atom falls from the level at −1.5 eV to the level at −3.4 eV. What is the wavelength of the emitted photon? (h = 6.63 × 10−34 J s, c = 3.00 × 108 m s−1, e = 1.60 × 10−19 C)
- Energy difference: ΔE = −1.5 − (−3.4) = 1.9 eV.
- In joules: 1.9 × 1.60 × 10−19 = 3.04 × 10−19 J.
- hc = 6.63 × 10−34 × 3.00 × 108 = 1.99 × 10−25 J m.
- λ = hc ÷ ΔE = (1.99 × 10−25) ÷ (3.04 × 10−19) = 6.5 × 10−7 m.
Answer: 6.5 × 10−7 m (about 650 nm, red light)