Chlorine is passed into hot concentrated sodium hydroxide: 3Cl2 + 6NaOH → 5NaCl + NaClO3 + 3H2O. What happens to the oxidation number of chlorine?
- In Cl2, an element, chlorine is 0.
- In NaCl it is −1, so five chlorine atoms are reduced, each gaining 1 electron.
- In NaClO3: (+1) + x + 3(−2) = 0, so x = +5. One chlorine atom is oxidised, losing 5 electrons.
- Electrons gained (5 × 1) = electrons lost (1 × 5), so the equation is balanced.
Answer: Chlorine goes from 0 to −1 and to +5: it is reduced and oxidised at once (disproportionation).