A galvanometer has a resistance of 99 Ω and gives full-scale deflection for 10 mA. What shunt resistance turns it into an ammeter reading up to 1.0 A?
- Current through the shunt = I − Ig = 1.0 − 0.010 = 0.99 A.
- P.d. across the galvanometer = IgRg = 0.010 × 99 = 0.99 V, and the shunt has the same p.d.
- Rs = 0.99 ÷ 0.99 = 1.0 Ω.
Answer: A 1.0 Ω shunt connected in parallel with the galvanometer