A Carnot engine works between a source at 527 °C and a sink at 127 °C. It takes in 1200 J of heat in each cycle. How much work does it do per cycle?
- Convert to kelvin: T1 = 527 + 273 = 800 K, T2 = 127 + 273 = 400 K.
- η = 1 − T2/T1 = 1 − 400 ÷ 800 = 0.50.
- W = η × Q1 = 0.50 × 1200 = 600 J.
Answer: 600 J per cycle (the other 600 J goes to the sink)