A ball is kicked from level ground at 20 m s−1 at 30° above the horizontal. Taking g = 10 m s−2, find its time of flight, maximum height and range.
- Vertical velocity = 20 sin 30° = 10 m s−1; horizontal velocity = 20 cos 30° = 17.3 m s−1.
- T = 2 × 10 ÷ 10 = 2.0 s.
- H = 102 ÷ (2 × 10) = 5.0 m.
- R = horizontal velocity × T = 17.3 × 2.0 = 34.6 m, about 35 m.
Answer: Time of flight 2.0 s, maximum height 5.0 m, range about 35 m.