The masses m kg of 20 parcels are grouped: 0 < m ≤ 2 (frequency 6), 2 < m ≤ 4 (frequency 10), 4 < m ≤ 8 (frequency 4). Calculate an estimate of the mean mass.
- Midpoints of the classes: 1, 3 and 6.
- Sum of (midpoint × frequency) = 1 × 6 + 3 × 10 + 6 × 4 = 6 + 30 + 24 = 60.
- Sum of frequencies = 6 + 10 + 4 = 20.
- Estimate of the mean = 60 ÷ 20 = 3.
Answer: 3 kg