Tangents from P touch a circle at A and B. Angle APB = 50°. C is a point on the major arc AB. Find angle ACB.
- PA = PB, so triangle PAB is isosceles: angle PAB = (180° − 50°) ÷ 2 = 65°.
- Angle PAB is the angle between tangent PA and chord AB.
- By the alternate segment theorem, angle ACB = angle PAB = 65°.
Answer: 65°