Find the nth term of the sequence 3, 10, 21, 36, …
- First differences: 7, 11, 15. Second differences: 4, 4, so the sequence is quadratic.
- Coefficient of n2 = 4 ÷ 2 = 2, so the formula starts with 2n2, which gives 2, 8, 18, 32.
- Subtract: 3 − 2 = 1, 10 − 8 = 2, 21 − 18 = 3, 36 − 32 = 4. What is left is n.
- Check with n = 4: 2 × 16 + 4 = 36.
Answer: nth term = 2n² + n