N-propylethanamide, CH3CONHCH2CH2CH3, is heated with NaOH(aq). What are the products?
- Hydrolysis breaks the C–N bond of the amide group, between CO and NH.
- The CH3CO– part becomes ethanoic acid, which reacts with the alkali to give sodium ethanoate, CH3COONa.
- The –NHCH2CH2CH3 part gains a hydrogen and leaves as the free amine, CH3CH2CH2NH2, because an amine does not react with alkali.
Answer: Sodium ethanoate and propylamine (propan-1-amine)