12.3 g of nitrobenzene (Mr 123) is reduced to phenylamine (Mr 93.0). The yield is 80%. What mass of phenylamine is obtained?
- One mole of nitrobenzene gives one mole of phenylamine.
- Moles of nitrobenzene = 12.3 ÷ 123 = 0.100 mol.
- Maximum mass of phenylamine = 0.100 × 93.0 = 9.30 g.
- Actual mass = 9.30 × 80 ÷ 100 = 7.44 g.
Answer: 7.44 g of phenylamine