A 0.20 kg mass oscillates with simple harmonic motion of angular frequency 10 rad s−1 and amplitude 0.060 m. What is its kinetic energy when its displacement is 0.020 m?
- Total energy = ½mω2x02 = 0.5 × 0.20 × 102 × 0.0602 = 0.5 × 0.20 × 100 × 0.0036 = 0.036 J.
- Potential energy at x = 0.020 m: ½mω2x2 = 0.5 × 0.20 × 100 × 0.0004 = 0.0040 J.
- Kinetic energy = 0.036 − 0.0040 = 0.032 J.
Answer: 0.032 J.