A body moves with simple harmonic motion of amplitude 0.050 m and period 0.40 s. What is its maximum speed, and what is its speed when its displacement is 0.030 m?
- ω = 2π ÷ T = 2π ÷ 0.40 = 15.7 rad s−1.
- Maximum speed v0 = ωx0 = 15.7 × 0.050 = 0.785 m s−1.
- At x = 0.030 m: √(x02 − x2) = √(0.0025 − 0.0009) = √0.0016 = 0.040 m.
- v = ω × 0.040 = 15.7 × 0.040 = 0.628 m s−1.
Answer: Maximum speed 0.79 m s−1; speed at 0.030 m is 0.63 m s−1.